decode SMS-SUBMIT

Read following  first : 

SMS-SUBMIT

Bit:

0,1-MTI (00 : Deliver , 01 Submit )

2-RD ( Reject Duplicate )

3,4-VPF

0 0 VP field is not present

0 1 Reserved

1 0 VP field present an integer represented (relative)

1 1 VP field present an semi-octet represented (absolute)

5-SRR (Status report request)

0:A status report is not requested

1:A status report is requested

6-UDHI

When TP-UDHI has value 1, the TP-UD field starts with User Data Header

7-RP

0:Reply Path parameter is not set in this PDU

1:Reply Path parameter is set in this PDU

SMS-SUBMIT :
0001000B915892214365F7000021493A283D0795C3F33C88FE06CDCB6E32885EC6D341EDF27C1E3E97E72E

-SMSC Defualt in cell phone : 00

-PDU TYPE : 01

00000001

Starting from right  :

bit0,1 : 01 >>> SMS-SUBMIT

bit2 : 0 >>> RD ( Reject duplicate)

bit3,4 : 00 >>> VP (Valudity period)

if 00 means not present

bit5: 0 >>> SRR (Status report requested) if 1 report requested

bit6: 0 >>> UDHI (User data header indicator) ... use for cancatenated message if 1 means header is present like 05 00 03 CC 02 01 (total02/number01)

bit7: 0 >>> RP ( Reply path ) 

-MR : 00 ( Message refrence by SMSC )

-DA : 0B915892214365F7

DA Len : 0B (Destination address Length)

International code : 91 : Display (+)

Number : 58 92 21 43 65 F7

reverse number from begining as 2 digits

58>>>85

So >>>> 85291234567

---From : [phone]

-PID : 00

-DCS : 00 (Alphabet) (Dada scheme coding)

if Unicode >>> 08

-UD : 21493A283D0795C3F33C88FE06CDCB6E32885EC6D341EDF27C1E3E97E72E

UDL : 21 in hex value (User data length)

UD : 493A283D0795C3F33C88FE06CDCB6E32885EC6D341EDF27C1E3E97E72E

decoding Data : 

-Reverse Hex value

2EE7973E1E7CF2ED41D3C65E88326ECBCD06FE883CF3C395073D283A49

-Hex to binary

00101110 11100111 10010111 00111110

00011110 01111100 11110010 11101101

01000001 11010011 11000110 01011110

10001000 00110010 01101110 11001011

11001101 00000110 11111110 10001000

00111100 11110011 11000011 10010101

00000111 00111101 00101000 00111010

01001001

Change octet to septet

--Get the number of zeros to be remove.

29×8−33×7=1

29×8-int(29×8/7)×7=1

-Remove 1 Zero from the left of first above binary ( octet : 00101110 )  and convert 7bits 7bits to hex value like as follows : 

0101110:2E

1110011:73

1100101:65

1100111:67

1100001:61

1110011:73

1110011:73

1100101:65

1101101:6D

0100000:20

1110100:74

1111000:78

1100101:65

1110100:74

0100000:20

1100100:64

1101110:6E

1100101:65

1110011:73

0100000:20

1101111:6F

1110100:74

0100000:20

1111001:79

1110011:73

1100001:61

1100101:65

0100000:20

1110011:73

1101001:69

0100000:20

1110100:74

1001001:49

-Binary to Hex and reverse

4974206973206561737920746F207365

6E642074657874206D65737361676573

2E

-Hex to text convertor : 

https://codebeautify.org/hex-string-converter

finally decoded done successfully !!!

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